Java Socket - Accepting multiple clients on single port

The concept is simple that after accepting the client on the socket, move that socket on to a separate thread and wait for next client to come to the same port. Code is below

public static void main(String args[]) {

            ServerSocket serverSocket = null;

            Socket socket = null;

            

            try {

                serverSocket = new ServerSocket(1234);

            } catch (IOException e) {

                e.printStackTrace();

                

            }

            while (true) {

                try {

                    socket = serverSocket.accept();

                } catch (IOException e) {

                    System.out.println("I/O error: " + e);

                }

              

                new ClientSocketProcessor(socket).start();

            }

        }

 public class ClientSocketProcessor extends Thread {

            protected Socket clientSocket;

            

            public ClientSocketProcessor(Socket socket) {

                this.clientSocket = socket;

            }

            

            public void run() {

System.out.println("accepted a client socket");

            PrintWriter out = new PrintWriter(clientSocket.getOutputStream(), true);

            System.out.println("created print writer out");

            BufferedReader in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));

            

            String inputLine, outputLine;

            

            StringBuffer requestBuffer = new StringBuffer();

            MSIPRequest request = new MSIPRequest();

            while ((inputLine = in.readLine()) != null) {

                System.out.println(inputLine);

}

            }

        }

References: 

https://docs.oracle.com/javase/tutorial/networking/sockets/clientServer.html

http://stackoverflow.com/questions/10131377/socket-programming-multiple-client-to-one-server